A Square Has A 40-Cm Diagonal How Long Is Each Side Of The Square ? Round To The Nearest Tenth Of A Centimeter

a square has a 40-cm diagonal how long is each side of the square ? round to the nearest tenth of a centimeter

 

Answer:

In solving this problem we use the Pythagorean Theorem which is:

c^2 = a^2 + b^2

40^2 = x^2 + x^2 (squared the following given)

1600 = 2x^2

1600 = 2x^2      (divide the given by 2)

  2          2

800 =x^2

√800 = √x^2   (find the square root)

   28. 3 = x

The final answer is x = 28.3.



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